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References and arrays

     PROBLEM: [email protected] (Andrew J. Jackson)

    I'm inquiring on how to declare a reference to an array of integers


    RESPONS: Efim Birger ([email protected])

    try this:

    typedef int *intp;
    int arr[10];
    intp& aaa = arr;


    RESPONSE: [email protected] (Fergus Henderson), 11 Aug 94

    This code is illegal. `aaa' is a (non-const) reference to a pointer to int.
    `arr' is an array of int, which will be converted to a pointer to int.
    The result of that conversion is a temporary.
    You are initializing a non-const reference with a temporary, which is illegal.


    RESPONSE: [email protected] (Bernd Eggink)

    There is no sUCh thing as a reference to an array.


    RESPONSE: [email protected] (Fergus Henderson)

    There most certainly is.
    (An array of references is illegal, but a reference to an array is quite OK.)

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